Naposledy aktivní 11 months ago

Definition of a Marchenko-Pastur distribution

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1 file changed, 2 insertions, 1 deletion

mp_distr.py

@@ -10,7 +10,8 @@ class MarchenkoPastur:
10 10 Parameters
11 11 ----------
12 12 ratio : float
13 - The ratio between the number of variables (columns) and the size of the sample (rows) contained in the data matrix. For numerical stability, it should be less than 1.
13 + The ratio between the number of variables (columns) and the size of the sample (rows) contained in the data matrix.
14 + For numerical stability, it should be less than 1.
14 15 sigma : float
15 16 The standard deviation of the distribution of values, by default, 1.0.
16 17

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Žádné změny

riccardo's Avatar riccardo revidoval tento gist 1 year ago. Přejít na revizi

1 file changed, 2 insertions, 2 deletions

mp_distr.py

@@ -27,8 +27,8 @@ class MarchenkoPastur:
27 27 self.sigma = sigma
28 28
29 29 # Compute the limits of the distribution
30 - self.l_bottom = sigma**2 * (1.0 - np.sqrt(self.ratio))**2
31 - self.l_upper = sigma**2 * (1.0 + np.sqrt(self.ratio))**2
30 + self.l_bottom = self.sigma**2 * (1.0 - np.sqrt(self.ratio))**2
31 + self.l_upper = self.sigma**2 * (1.0 + np.sqrt(self.ratio))**2
32 32
33 33 def pdf(self, x: float | ArrayLike) -> float | ArrayLike:
34 34 """

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1 file changed, 4 insertions, 1 deletion

mp_distr.py

@@ -47,7 +47,10 @@ class MarchenkoPastur:
47 47 if not np.isscalar(x):
48 48 return np.vectorize(self.pdf, otypes=[float])(x)
49 49
50 + if x == 0.0:
51 + return 0.0
52 +
50 53 num = np.sqrt(max(self.l_upper - x, 0.0) * max(x - self.l_bottom, 0.0))
51 54 den = 2.0 * np.pi * self.sigma**2 * self.ratio * x
52 55
53 - return float(num / den) if den != 0.0 else 0.0
56 + return float(num / den)

riccardo's Avatar riccardo revidoval tento gist 1 year ago. Přejít na revizi

1 file changed, 53 insertions

mp_distr.py(vytvořil soubor)

@@ -0,0 +1,53 @@
1 + import numpy as np
2 +
3 + from numpy.typing import ArrayLike
4 +
5 + class MarchenkoPastur:
6 + """Definition of a Marchenko-Pastur distribution"""
7 +
8 + def __init__(self, ratio: float, sigma: float = 1.0):
9 + """
10 + Parameters
11 + ----------
12 + ratio : float
13 + The ratio between the number of variables (columns) and the size of the sample (rows) contained in the data matrix. For numerical stability, it should be less than 1.
14 + sigma : float
15 + The standard deviation of the distribution of values, by default, 1.0.
16 +
17 + Raises
18 + ------
19 + ValueError
20 + If ratio or sigma are not strictly positive.
21 + """
22 + if ratio <= 0.0:
23 + raise ValueError("The ratio must be strictly positive, but found %s <= 0.0!" % ratio)
24 + self.ratio = ratio
25 + if sigma <= 0.0:
26 + raise ValueError("The standard deviation must be strictly positive, but found %s <= 0.0!" % sigma)
27 + self.sigma = sigma
28 +
29 + # Compute the limits of the distribution
30 + self.l_bottom = sigma**2 * (1.0 - np.sqrt(self.ratio))**2
31 + self.l_upper = sigma**2 * (1.0 + np.sqrt(self.ratio))**2
32 +
33 + def pdf(self, x: float | ArrayLike) -> float | ArrayLike:
34 + """
35 + Return the value of the probability distribution function.
36 +
37 + Parameters
38 + ----------
39 + x : float | ArrayLike
40 + The value(s) at which to compute the PDF.
41 +
42 + Returns
43 + -------
44 + float | ArrayLike
45 + The value(s) of the PDF
46 + """
47 + if not np.isscalar(x):
48 + return np.vectorize(self.pdf, otypes=[float])(x)
49 +
50 + num = np.sqrt(max(self.l_upper - x, 0.0) * max(x - self.l_bottom, 0.0))
51 + den = 2.0 * np.pi * self.sigma**2 * self.ratio * x
52 +
53 + return float(num / den) if den != 0.0 else 0.0
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